Updating xml using xpath java

NODESET); “, so to match a result we manipulate the string to convert it to the correct data format used by our document and we do it by using one of the functions provided by XPath If our xml document has a namespace defined as it is in the example_used here, the rules to retrieve the data we need are going to change since our xml starts like this: By doing this we can check each type of node we find and remove those ones we don't need. These kind of expressions are called predicates and they are an easy way to locate specific data over a document, for example: Document xml Document = builder.parse(File()); this.clean(xml Document); XPath x Path = XPath Instance()XPath(); String expression = "//Tutorial[descendant::title[text()=" "'" name "'" ""; node List = (Node List) x Path.compile(expression).evaluate(xml Document, XPath Constants.

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NODESET); “, so to match a result we manipulate the string to convert it to the correct data format used by our document and we do it by using one of the functions provided by XPath If our xml document has a namespace defined as it is in the example_used here, the rules to retrieve the data we need are going to change since our xml starts like this: By doing this we can check each type of node we find and remove those ones we don't need.

These kind of expressions are called predicates and they are an easy way to locate specific data over a document, for example: Document xml Document = builder.parse(File()); this.clean(xml Document); XPath x Path = XPath Instance()XPath(); String expression = "//Tutorial[descendant::title[text()=" "'" name "'" "]]"; node List = (Node List) x Path.compile(expression).evaluate(xml Document, XPath Constants.

SAXParse Exception; try { Document Builder Factory doc Builder Factory = Document Builder Instance(); Document Builder doc Builder = doc Builder Document Builder(); Document doc = doc Builder.parse (new File("c:\\tmp\\my.xml")); // normalize text representation Document Element().normalize(); println ("Root element of the doc is " Document Element()Node Name()); Node List list Of Books = Elements By Tag Name("book"); int total Books = list Of Length(); println("Total no of books : " total Books); for(int i=0; i Here is an example of processing xpath with vtd-xml...

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updating xml using xpath java-88updating xml using xpath java-86updating xml using xpath java-1

We can look for an element based on any given id just by filtering: Document Builder Factory builder Factory = Document Builder Instance(); Document Builder builder = builder Document Builder(); Document xml Document = builder.parse(File()); XPath x Path = XPath Instance()XPath(); String expression = "/Tutorials/Tutorial[@tut Id=" "'" id "'" "]"; node = (Node) x Path.compile(expression).evaluate(xml Document, XPath Constants.If you want to * update an attribute, just pass * * "/project/@name" (update the value of the "name" * attribute in the "project" element.) * * "/project/test[last()]/@dude" (update the value of the * "dude" attribute in the last element called "test") * * "/project/test[@price>50.00]" (update the value of the test * content for all test elements that have an attribute called "price" * whose value is greater than 50.00 ) * * "/project/test[@price>50.00]/@dude" (update the value of the * "dude" attribute for all test elements that have an attribute * called "price" whose value is greater than 50.00 ) * * "/project/test[@dude='old']" (update the value of the * "test" element for all test elements that have an attribute * called "dude" whose value is equal to the string 'old') * * * * This implementation uses DOM, so it may not be suitable for very large * (many megabyte) files.* * @param file In the available XML file you want to update. Document; public class Default Parser File Input Stream file IS = new File Input Stream(File()); Document Builder Factory builder Factory = Document Builder Instance(); Document Builder builder = builder Document Builder(); Document xml Document = builder.parse(file IS); XPath x Path = XPath Instance()XPath(); String expression = "/Tutorials/Tutorial"; node List = (Node List) x Path.compile(expression).evaluate(xml Document, XPath Constants.As you can see, there is a wide range of possibilities on how to handle these kind of files.

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